Yesterday's Answer: perimeter = 30', area = 36 square feet; length x width equals the number of 1' x 1' squares in an area.
Congratulations to Bryce!
Today's Problem (5 points):
How many distinct isosceles triangles exist with a perimeter of 99 inches and side lengths that are positive whole numbers?
Due November 13
Answer to last week's question: 94 feet
Congratulations to Bryce for getting it right!
Find the perimeter and area of a rectangle that is 12' wide and 3' high. Why do we always talk about area in terms of square measures?
Congratulations to Bryce for getting it right!
Find the perimeter and area of a rectangle that is 12' wide and 3' high. Why do we always talk about area in terms of square measures?
Due November 6
Last Week's Answer:The total is 75, or use Gauss’s formula for the sum of the first n numbers n(n + 1)/2. Use the formula when n = 12 to get 12(13)/2 = 78, then subtract the first two terms not in the table, 1 and 2.Congratulations to Bryce for getting it right!
This Week's Question:
A Super Ball rebounds half the height from the height it is dropped. One day, a mathematics teacher drops a Super Ball from the roof of the school. If the roof is 32 feet off the ground, what is the total distance (up and down) that the ball will have traveled when it strikes the ground for the sixth time?
This Week's Question:
A Super Ball rebounds half the height from the height it is dropped. One day, a mathematics teacher drops a Super Ball from the roof of the school. If the roof is 32 feet off the ground, what is the total distance (up and down) that the ball will have traveled when it strikes the ground for the sixth time?
Due October 30
Last Week's Answer:
18. February 29 occurs every four years. 2004 is a leap year, so the man celebrated his February 29 birthday in these years: 1932, 1936, 1940, 1944, 1948, 1952, 1956, 1960, 1964, 1968, 1972, 1976, 1980, 1984, 1988, 1992, 1996, and 2000 but not 2004 because he died before his birthday.
Congratulations to Bryce for getting it right!
This Week's Problem:
In a typical deck of 52 playing cards, the 4 of hearts card has 6 hearts on it, not 4: 4 hearts in the center of the card and 1 heart in both the upper-left corner and the lower-right corner. How many total hearts would you see when looking at the ace of hearts card along with the cards 2 of hearts through the 10 of hearts?
18. February 29 occurs every four years. 2004 is a leap year, so the man celebrated his February 29 birthday in these years: 1932, 1936, 1940, 1944, 1948, 1952, 1956, 1960, 1964, 1968, 1972, 1976, 1980, 1984, 1988, 1992, 1996, and 2000 but not 2004 because he died before his birthday.
Congratulations to Bryce for getting it right!
This Week's Problem:
In a typical deck of 52 playing cards, the 4 of hearts card has 6 hearts on it, not 4: 4 hearts in the center of the card and 1 heart in both the upper-left corner and the lower-right corner. How many total hearts would you see when looking at the ace of hearts card along with the cards 2 of hearts through the 10 of hearts?
October 23
Last week's answer:
8. In the mouse's first trip around the clock, it eats the cheese on all the odd numbers. When it has eaten the cheese on number 11, the following numbers still have cheese: 12, 2, 4, 6, 8, 10. Remember, it must eat every other piece encountered. Therefore, after 11, it will eat 2, 6, and 10. The mouse is now on 10, and cheese remains on 12, 4, and 8. It will then eat the cheese on 4, leaving 8 and 12. It will skip 8 and eat 12's cheese, leaving 8 as the last number containing cheese.
Thanks to all who tried.
Today's Problem:
A man was born on February 29, 1928. He died on January 29, 2004. How many actual birthdays did he get to celebrate during his life (not counting the day he was born as a birthday)? Hint: Don’t forget about leap years.
8. In the mouse's first trip around the clock, it eats the cheese on all the odd numbers. When it has eaten the cheese on number 11, the following numbers still have cheese: 12, 2, 4, 6, 8, 10. Remember, it must eat every other piece encountered. Therefore, after 11, it will eat 2, 6, and 10. The mouse is now on 10, and cheese remains on 12, 4, and 8. It will then eat the cheese on 4, leaving 8 and 12. It will skip 8 and eat 12's cheese, leaving 8 as the last number containing cheese.
Thanks to all who tried.
Today's Problem:
A man was born on February 29, 1928. He died on January 29, 2004. How many actual birthdays did he get to celebrate during his life (not counting the day he was born as a birthday)? Hint: Don’t forget about leap years.
Due October 16
Small pieces of cheese are placed over each of twelve numbers on the face of a circular clock. A mouse eats the cheese over the number 1 and walks clockwise around the clock, eating every other piece of cheese. What number will be under the last uneaten piece of cheese?
Subscribe to:
Posts (Atom)