October 23

Last week's answer:
8. In the mouse's first trip around the clock, it eats the cheese on all the odd numbers. When it has eaten the cheese on number 11, the following numbers still have cheese: 12, 2, 4, 6, 8, 10. Remember, it must eat every other piece encountered. Therefore, after 11, it will eat 2, 6, and 10. The mouse is now on 10, and cheese remains on 12, 4, and 8. It will then eat the cheese on 4, leaving 8 and 12. It will skip 8 and eat 12's cheese, leaving 8 as the last number containing cheese.
Thanks to all who tried.

Today's Problem:
A man was born on February 29, 1928. He died on January 29, 2004. How many actual birthdays did he get to celebrate during his life (not counting the day he was born as a birthday)? Hint: Don’t forget about leap years.